javascript - how to have image appear on mouseover and hidden on mouseout -


i trying have image disappear on mouse out. have image appear on mouse on want hidden on mouse out. have current code below help?

var fullpic = new array(4);    (var i=0;i<fullpic.length;i++)        fullpic[i] = new image(515,385);    fullpic[0].src = "images/frenchquarter.jpg";  fullpic[1].src = "images/goldengatebridge.jpg";  fullpic[2].src = "images/nazarethbay.jpg";  fullpic[3].src = "images/thealamo.jpg";      function displayfull(i){      document.getelementbyid("img-cover").src=fullpic[i].src;  }      /*this function have make image hidden */    function hidefull(i){      document.getelementbyid("img-cover").css.visibility=hidden;  }    var fullbanner = new array(4);    (var i=0;i<fullbanner.length;i++)        fullbanner[i] = new image(468,60);    fullbanner[0].src = "images/banner1.gif";  fullbanner[1].src = "images/banner2.gif";  fullbanner[2].src = "images/banner3.gif";  fullbanner[3].src = "images/banner4.gif";    var n = 0;    window.addeventlistener("load",showfull,false);    function showfull(){        setinterval("showpic()",3000);      }    function showpic(){        document.getelementbyid("banner").src=fullbanner[n].src;      n++;      if(n>3)          n=0;    }
<!doctype html>  <html>      <head>        <meta charset = "utf-8">        <title></title>        <link rel = "stylesheet" type = "text/css" href = "style.css">        <script src = "function.js"></script>      </head>        <body>          <div id = "banner-wrapper">              <img id = "banner" src = "images/banner1.gif">          </div>            <div id = "thumbs">              <img class = "thumb-img" src = "images/frenchquarter_small.jpg" onmouseover="displayfull(0)" onmouseout= "hidefull(0)">              <img class = "thumb-img" src = "images/goldengatebridge_small.jpg" onmouseover="displayfull(1)" onmouseout= "hidefull(1)">              <img class = "thumb-img" src = "images/nazarethbay_small.jpg" onmouseover="displayfull(2)" onmouseout= "hidefull(2)">              <img class = "thumb-img" src = "images/thealamo_small.jpg" onmouseover="displayfull(3)" onmouseout= "hidefull(3)">             </div>            <div id = "main-img">              <img id = "img-cover" src = "">            </div>        </body>  </html>

check error console. you'll see:

error: {   "message": "referenceerror: hidden not defined",   "filename": "http://stacksnippets.net/js",   "lineno": 61,   "colno": 5 }

hidden not defined

because it's supposed string. put quotes..

function hidefull(i){     document.getelementbyid("img-cover").style.visibility='hidden'; }

Comments

Post a Comment

Popular posts from this blog

sql server - Cannot query correctly (MSSQL - PHP - JSON) -

i have little problem on project. , turns out query result returns nothing when value of first name or last name has 'ñ' in it. here's code config.php: <?php ini_set('mssql.charset', 'utf-8'); header('content-type: text/html; charset=utf-8'); $servername = "192.168.1.21"; /* ip add of db server */ $connection = array("database" => "db", "uid" => "?", "pwd" => "***"); $conn = sqlsrv_connect($servername, $connection); if(!$conn){ echo "connection not established."; die(print_r(sqlsrv_errors(), true)); } ?> myquery: $idnumber = $_post["idnum"]; $response = array(); $query2 = "select clname, cfname, cmname, cqualifier student cidno = '$idnumber'"; try{ $stmt2 = sqlsrv_query($conn, $query2); } catch(pdoexeption $ex){ $response["success"] = 0; $response["message"] = "d...
Read more

php - trouble displaying mysqli database results in correct order -

i have table in database stores events , date expire. want display events on website display current events first expired events after? i have tried following sql $sql = "select noticeid, notice, noticedesc, noticeimg, noticedate, expirydate tbl_notices group noticeid ,expired order expirydate asc"; but returns expired results first due expirydate being ordered asc in query. my tbl_notice structure looks this noticeid => int(4) notice => varchar(100) noticedesc => text noticedate => timestamp noticeimg => varchar(40) expirydate => datetime expired => int(1) 0 current or 1 expired my php code is $sql = "select noticeid, notice, noticedesc, noticeimg, noticedate, expirydate tbl_notices group noticeid ,expired order expirydate asc"; $result = mysqli_query($conn,$sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { ...
Read more

C++ Linked List -

i trying create linked list download txt file , use linked list handle file line line. when handling downloaded linked list operations performed on such text editor would. encountering problems however. seems "node(string value)" section of code has wrong though original node() declaration no arguments passes. unable figure out quite is. node.h class node { public: node(); node(string value); void setnext(node *nextnode); // allows user set "next" pointer of node points friend class linkedlist; private: string data; // data box node* next; // pointer box }; node.cpp # include <string> # include "node.h" using namespace std; node::node() { data = ""; next = null; } node::node(string value) { data = value; next = null; } void node::setnext(node *nextnode) // allows user set "next" pointer of node points { this->next = nextnode; } your #include <string> ...
Read more