python - How to slice a list of strings with space delimiter? -


this question has answer here:

i have list (original_list) made of multiple strings space in each element below. how create separate list of last string (or file name excluding else) of each element original list?

original_list = ['-rw-rw-r-- 1 root root   134801 nov  2 14:27 aa_base-13.txt',  '-rw-rw-r-- 1 root root 58630 nov  2 14:27 aaa_base-extras.txt',  '-rw-rw-r-- 1 root root   300664 nov  2 14:27 aaa_base-extras.txt'] expected output th new list should below:

extracted_list 

['aa_base-13.txt', 'aaa_base-extras.txt', 'aaa_base-extras.txt']

that's how:

new_list = [x.split()[-1] x in original_list]

please include attempts in future when asking questions.

there no argument passed split can see , means takes default space. then, newly created sublists sliced , last item taken (that's [-1] for). try removing see produces.

of course of times in programming (if not always) there many ways task. example this:

new_list = [y item in [x.split() x in original_list] y in item if '.' in y]

with second 1 looking substrings contain dots '.'. replace '.txt'. that's more solid way filenames or filenames of specific extension since bound contain @ least 1 dot.

what 2 approaches have in common list comprehensions. core concept in python , suggest looking @ if serious this.

hope helps!


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