c++ - reduce a 5x5 matrix to an 25 element array in c -

i have following homework problem witch can't seem find solution. problem: create 5x5 matrix of integers , check if of elements of matrix in interval [-10,15], , ones belong interval add array of 25 elements. program should implemented in c/c++. question: have written following code , problem have when try transfer elements have found fit condition, in nested for-loop. trouble when cycle through 5 elements , @ same time iterate 25 elements. how can this? here code:

#include <stdio.h> #include "stdafx.h"   void main() {     int i, j, k, l, m;     int a[5][5];     int b[25];       printf("please enter elements of matrix:\n");      ( = 0; < 5; i++)     {         ( k = 0; k < 5; k++)         {             scanf_s("%d", &a[i][k]);         }     }      ( k = 0; k < 25; k++)     {         ( l = 0; l < 5; l++)         {             if (a[k][l] > -10 && a[k][l] < 15) {                 b[k] = a[k][l];             }         }     }     printf("the elements in range [-10, 15],   following:\n");      (m = 0; m < 25; m++)     {         printf("%d\n", b[m]);     } } 

i think, have squeezed both loops one. please see below. while accepting input, there checking condition , putting new 1d array. since,i have counter 1d array(which increments new numbers inserted), while displaying; can use well.

    #include <stdio.h>       int main()     {         int a[5][5];         int b[15];         int c=0; printf("please enter elements of matrix:\n");         for(int i=0;i<5; i++){             for(int j=0;j<5;j++){                scanf("%d",&a[i][j]);                 if(a[i][j]>-10 && a[i][j]<15){                     b[c++]=a[i][j];                 }             }         } printf("\nthe numbers meet condition are:\n");         for(int i=0;i<c;i++)         printf("%d,",b[i]);           return 0;     }