ios - Textfield not working once clicked on in the simulator -


i using google maps sdk , have map route user wherever specific location. user able input want go, rather being routed same location. added text field gui , whenever run app in simulator , click textfield, no keyboard comes , acts though did not tap on it.

here how have set project:

import uikit import googlemaps import googleplaces import coredata  class viewcontroller: uiviewcontroller, cllocationmanagerdelegate, uitextfielddelegate {  let locationmanager = cllocationmanager()     var currlocation: cllocationcoordinate2d!     var keyy = "mykeyishere"     var didfindmylocation = false     var count: int = 0     var button = uibutton()     var latitude = uitextfield()     var longitude = uitextfield()     var path = gmsmutablepath()  super.viewdidload()         let blah = gmscameraposition.camera(withlatitude: 39.8282, longitude: -98.5795, zoom: 25.0)         mapview.camera = blah         locationmanager.delegate = self         locationmanager.requestwheninuseauthorization()         mapview.addobserver(self, forkeypath: "mylocation", options: nskeyvalueobservingoptions.new, context: nil)          currlocation = mapview.mylocation?.coordinate          button = uibutton(type: .system)         button.frame = cgrect(x: 135, y: 40, width: 100, height: 40)         button.backgroundcolor = uicolor.clear         button.layer.cornerradius = 5         button.layer.borderwidth = 1         button.layer.bordercolor = uicolor.blue.cgcolor         button.settitle("route", for: uicontrolstate.normal)         button.addtarget(self, action: #selector(viewcontroller.buttonpressed), for: uicontrolevents.touchupinside)          latitude = uitextfield()         latitude.frame = cgrect(x: 5, y: 90, width: 175, height: 35)         latitude.backgroundcolor = uicolor.white         latitude.layer.cornerradius = 5         latitude.layer.borderwidth = 1         latitude.layer.bordercolor = uicolor.black.cgcolor         latitude.isuserinteractionenabled = true         latitude.text = " enter latitude"         latitude.keyboardtype = uikeyboardtype.numbersandpunctuation         self.latitude.delegate = self          longitude = uitextfield()         longitude.frame = cgrect(x: 195, y: 90, width: 175, height: 35)         longitude.backgroundcolor = uicolor.white         longitude.layer.cornerradius = 5         longitude.layer.borderwidth = 1         longitude.layer.bordercolor = uicolor.black.cgcolor         longitude.isuserinteractionenabled = true         longitude.text = " enter longitude"         longitude.keyboardtype = uikeyboardtype.numbersandpunctuation         self.longitude.delegate = self          self.view.addsubview(latitude)         self.view.addsubview(button)         self.view.addsubview(longitude)     }

there more feel relevant problem. ive added 2 text fields here, , neither work! please help!

you able type in textfield using macs keyboard. if want keyboard show press cmd + k in simulator toggle software keyboard.

the keyboard show on device.


Comments

Post a Comment

Popular posts from this blog

sql server - Cannot query correctly (MSSQL - PHP - JSON) -

i have little problem on project. , turns out query result returns nothing when value of first name or last name has 'ñ' in it. here's code config.php: <?php ini_set('mssql.charset', 'utf-8'); header('content-type: text/html; charset=utf-8'); $servername = "192.168.1.21"; /* ip add of db server */ $connection = array("database" => "db", "uid" => "?", "pwd" => "***"); $conn = sqlsrv_connect($servername, $connection); if(!$conn){ echo "connection not established."; die(print_r(sqlsrv_errors(), true)); } ?> myquery: $idnumber = $_post["idnum"]; $response = array(); $query2 = "select clname, cfname, cmname, cqualifier student cidno = '$idnumber'"; try{ $stmt2 = sqlsrv_query($conn, $query2); } catch(pdoexeption $ex){ $response["success"] = 0; $response["message"] = "d...
Read more

php - trouble displaying mysqli database results in correct order -

i have table in database stores events , date expire. want display events on website display current events first expired events after? i have tried following sql $sql = "select noticeid, notice, noticedesc, noticeimg, noticedate, expirydate tbl_notices group noticeid ,expired order expirydate asc"; but returns expired results first due expirydate being ordered asc in query. my tbl_notice structure looks this noticeid => int(4) notice => varchar(100) noticedesc => text noticedate => timestamp noticeimg => varchar(40) expirydate => datetime expired => int(1) 0 current or 1 expired my php code is $sql = "select noticeid, notice, noticedesc, noticeimg, noticedate, expirydate tbl_notices group noticeid ,expired order expirydate asc"; $result = mysqli_query($conn,$sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { ...
Read more

C++ Linked List -

i trying create linked list download txt file , use linked list handle file line line. when handling downloaded linked list operations performed on such text editor would. encountering problems however. seems "node(string value)" section of code has wrong though original node() declaration no arguments passes. unable figure out quite is. node.h class node { public: node(); node(string value); void setnext(node *nextnode); // allows user set "next" pointer of node points friend class linkedlist; private: string data; // data box node* next; // pointer box }; node.cpp # include <string> # include "node.h" using namespace std; node::node() { data = ""; next = null; } node::node(string value) { data = value; next = null; } void node::setnext(node *nextnode) // allows user set "next" pointer of node points { this->next = nextnode; } your #include <string> ...
Read more