python - Make a function sleep until another function is done -


so, i'm trying make blackjack game. simple one, if may add.

my code looks this:

def cmd_blackjack(message):     playblackjack(message, player=true)  def dealcard():     card = random.randrange(1, 11)     return card  def dealhand(message, player=false, dealer=false):     card1 = dealcard()     card2 = dealcard()     if player:         client.send_message(message.channel,                                'blackjack: cards: %s , %s \n type !hitme more cards or !stay stay' % (card1, card2))     if dealer:         client.send_message(message.channel,                                "blackjack: dealer's cards: %s %s" % (card1, card2))     return card, card2  def playblackjack(message, player=false, dealer=false):     dealhand(player)

and pretty i'm trying archieve:

def playblackjack(message, player=false, dealer=false):     dealhand(player)     // when player has input !hitme more cards     if not playerhastypedhitme in 300 secs:         return      dealhand(player=false, dealer=true)     // code continues

so basically, need figure out (non-retarded, know can lists, example) way make function wait user input. make function send 'ok, continue' message function.

i know has been asked before probably, it's hard describing in search terms want accomplish

you don't need sleep. if understood correctly, want wait user input.

python's input() function you.


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