python - Type Error when running function -


i'm trying use fileinput replace line in file, if word in line. appends file. runs gives me typeerror, i'm trying figure out error is.

tagname = 'somestring' def add_tags():         line in fileinput.fileinput('/tmp/hosttags.mk',inplace=1):             if 'end_tags' in line:                 line = line.replace(""" ('end_tags',""", """('%s', u'/%s',  [('%s', u'%s tag', [])]),  ('end_tags',  u'testing/end_tags_start', [('end_tag_id', u'end_tag_description', [])])]""") % ( tagname, tagname, tagname, tagname)             print line.strip()

error:

traceback (most recent call last):   file "./tag_update.py", line 57, in <module>     checkmk_srv_tag_update()   file "./tag_update.py", line 54, in checkmk_srv_tag_update     add_tags()   file "./tag_update.py", line 45, in add_tags     [('end_tag_id', u'end_tag_description', [])])]""") % ( tagname, tagname, tagname, tagname) typeerror: not arguments converted during string formatting

end result of file being updated:

('house', u'/house', [('house', u'house tag', [])]), ('somestring', u'/somestring',   [('somestring', u'somestring tag', [])]),  ('end_tags',  u'testing/end_tags_start', [('end_tag_id', u'end_tag_description', [])])]

thanks

you have wrongly put bracket, doing

line = line.replace("xxx", "%s %s") % (tagname, tagname)

where suppose be

line = line.replace("xxx", "%s %s" % (tagname, tagname) )

lets line = 'xxx', replace text match, works because 1st replace become "%s %s" % (tagname, tagname)

when replace text not match, fail because become original line 'xxx' % (tagname, tagname) ,thus error

the error can fix changing if part into

if " ('end_tags'," in line:
  • fix wrong bracket
  • as luke woodward mention, if checking not matching replace text portion, can remove if part, code work replace not happen when replace text not matching
  • instead of %, suggest use string format line = line.replace("xxx", "{0} {0}".format(tagname) )

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