javascript - Fixed - AJAX and datalists -


i'm trying use xml list of cities website, go through , add each of cities datalist when put in input filter cities in list.

example of city list:

aleppo alexandria alger almaty ankara anshan baghdad baku bandung bangalore bangkok barcelona

*[each city name on new line]

current html:

<div id="namearea">         <h2>city name:</h2>          <div>             <input id="citiesinput" list="cities">             <datalist id="cities"></datalist>              <button id="search">                 search             </button>              <span class="loading" id="loadingnames">                 loading...             </span>         </div>     </div>

current js code:

window.onload = function() {     var request = new xmlhttprequest();     request.onload = processcities;     request.open("get", "url", true);     request.send(); };

inspecting page firebug shows nothing being added datalist, i'm wondering i'm doing wrong. tried using .responsetext rather .responexml didn't make difference. can me?

[edit] progress has been made. changed processcities() function to:

function processcities() {     var response = this.responsetext;     var city = response.split("\n");     var options = "";      for(var = 0; < response.length; i++) {         options += "<option value='"+city[i]+"'>\n";     }     document.getelementbyid("cities").innerhtml = options; }

this code seems work.

thanks help.

here example of making request. if getting xml, you'll have parse it. it's better if json.

var request = new xmlhttprequest();  request.open('get', '/my/url', true);    request.onload = function() {    if (request.status >= 200 && request.status < 400) {      // success!      var data = json.parse(request.responsetext);    } else {      // reached our target server, returned error      }  };    request.onerror = function() {    // there connection error of sort  };    request.send();


Comments

Post a Comment

Popular posts from this blog

sql server - Cannot query correctly (MSSQL - PHP - JSON) -

i have little problem on project. , turns out query result returns nothing when value of first name or last name has 'ñ' in it. here's code config.php: <?php ini_set('mssql.charset', 'utf-8'); header('content-type: text/html; charset=utf-8'); $servername = "192.168.1.21"; /* ip add of db server */ $connection = array("database" => "db", "uid" => "?", "pwd" => "***"); $conn = sqlsrv_connect($servername, $connection); if(!$conn){ echo "connection not established."; die(print_r(sqlsrv_errors(), true)); } ?> myquery: $idnumber = $_post["idnum"]; $response = array(); $query2 = "select clname, cfname, cmname, cqualifier student cidno = '$idnumber'"; try{ $stmt2 = sqlsrv_query($conn, $query2); } catch(pdoexeption $ex){ $response["success"] = 0; $response["message"] = "d...
Read more

php - trouble displaying mysqli database results in correct order -

i have table in database stores events , date expire. want display events on website display current events first expired events after? i have tried following sql $sql = "select noticeid, notice, noticedesc, noticeimg, noticedate, expirydate tbl_notices group noticeid ,expired order expirydate asc"; but returns expired results first due expirydate being ordered asc in query. my tbl_notice structure looks this noticeid => int(4) notice => varchar(100) noticedesc => text noticedate => timestamp noticeimg => varchar(40) expirydate => datetime expired => int(1) 0 current or 1 expired my php code is $sql = "select noticeid, notice, noticedesc, noticeimg, noticedate, expirydate tbl_notices group noticeid ,expired order expirydate asc"; $result = mysqli_query($conn,$sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { ...
Read more

C++ Linked List -

i trying create linked list download txt file , use linked list handle file line line. when handling downloaded linked list operations performed on such text editor would. encountering problems however. seems "node(string value)" section of code has wrong though original node() declaration no arguments passes. unable figure out quite is. node.h class node { public: node(); node(string value); void setnext(node *nextnode); // allows user set "next" pointer of node points friend class linkedlist; private: string data; // data box node* next; // pointer box }; node.cpp # include <string> # include "node.h" using namespace std; node::node() { data = ""; next = null; } node::node(string value) { data = value; next = null; } void node::setnext(node *nextnode) // allows user set "next" pointer of node points { this->next = nextnode; } your #include <string> ...
Read more