php - If statement with or (||) argument does not work with in_array method -

i have snippet of code

public function dynamicslugaction(request $request, $slug) {     $array1 = ["coffee", "milk", "chocolate", "coca-cola"];     $array2 = ["water", "juice", "tomato-juice", "ice-tea"];     if (!in_array($slug, $array1) || !in_array($slug, $array2)) {         throw new \exception("the var " . strtoupper($slug) . " not exist parameter (slug): " . $slug);     } } 

even if write right value wich exist in array1 or array2 have error launched throw new \exception.

if remove or clause in if statement , write right value, no error occured can't check second condition.

where wrong in if statement?

you need use logical , (&&) not or. saying

if $slug isn't in array1 or isn't in array 2, throw exception. not throw exception slug value need in both array 1 , array 2.

what want (i assume), if if value of slug isn't in either array throw exception, if exists in 1 of arrays, nothing , carry on. change if statement to:

if (!in_array($slug, $array1) && !in_array($slug, $array2)) {   throw new \exception("the var ".strtoupper($slug)." not exist parameter (slug): ".$slug); }