linux - How to pass variable within printf -

i trying echo variable within printf. first prompt user input using command below

printf 'specify lrus [default 128]:         ' ;read -r lrus

next prompts user again see if wants input used previous question:

printf 'are sure want $lrus lrus:       ' ;read -r ans

for example output below:

specify lrus [default 128]:     60 sure want 60 lrus:  yes

the above output trying achieve allowing pass previous input variable next question using printf.

your problem using single-quotes. parameters not expanded within single quotes.

parameters expanded in double-quotes, though:

printf "are sure want $lrus lrus: "

note there's no need separate print; it's better use -p argument read (that understands terminal width, 1 thing):

read -p "specify lrus [default 128]: " -r lrus read -p "are sure want $lrus lrus? " -r ans

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