Counting occurrences in array java -


i want compute occurrences of each number in java array (like 1=?, 2=?, 3=?). how can array store more 10 value?

int [] arrynum = new int[]{4,4,4,3,4,5,4,3,4,4,4,5,4,5,5,5,4,3,2,15,4,3,4,6,4,3,4,5,4,2,4,5,4,3,2,5,4,3,5,4,0,4,3,4,5,4,3,0,4,5,4,3,5,4,2,3,2,3,4};      int[] counter = new int[] { 0, 0, 0, 0, 0,0 };     (int = 0; < arrynum.length; i++) {         counter[arrynum[i] ]++;     }      (int = 0; < counter.length; i++){         system.out.println((i + 1) + ":" + counter[i]);     } 

public static void main(string[] args){     int[] arrynum = new int[] { 4, 4, 4, 3, 4, 5, 4, 3, 4, 4, 4, 5, 4, 5, 5, 5, 4, 3, 2, 15, 4,             3, 4, 6, 4, 3, 4, 5, 4, 2, 4, 5, 4, 3, 2, 5, 4, 3, 5, 4, 0, 4, 3, 4, 5, 4, 3, 0, 4,             5, 4, 3, 5, 4, 2, 3, 2, 3, 4 };     map<integer, integer> lookup = new hashmap<>();     (int key : arrynum) {         if(lookup.containskey(key)) {             lookup.put(key, lookup.get(key) + 1);         } else {             lookup.put(key, 1);         }     }      (integer keys : lookup.keyset()) {         system.out.println(keys + " found " + lookup.get(keys) + " times");     }  }

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