java - Overloading or a normal method -


i gonna put question have clear idea overloading concept in java . per understanding while method resolution in overloading compiler method signature should have same method name , different argument types . if return type different ??

class test{     public void m1(int i) {     system.out.println(" int arg"); }  public int m1(string s) {     system.out.println("string-arg");     return (5+10); }  public static void main (string[] args) throws java.lang.exception {     test t = new test();     t.m1(5);     int = t.m1("ani");     system.out.println(i); }} 

the above program running . doubt here , method m1() overloaded ?? has different return type . please make clear. in advance

in java methods identified name , arguments' classes , amount. return type doesn't identify method. reason following code illegal:

public void m1(string i) {      system.out.println(" int arg"); }  public int m1(string s) {      system.out.println("string-arg");     return (5+10); } 

if 2 methods of class (whether both declared in same class, or both inherited class, or 1 declared , 1 inherited) have same name signatures not override-equivalent, method name said overloaded. (...) when method invoked (§15.12), number of actual arguments (and explicit type arguments) , compile-time types of arguments used, @ compile time, determine signature of method invoked (§15.12.2). if method invoked instance method, actual method invoked determined @ run time, using dynamic method lookup (§15.12.4)

summarizing, 2 methods same name can return different types, it's not being taken account when deciding method call. jvm first decides method call , later checks if return type of method can assigned variable.

example (try avoid such constructions):

public int pingpong(int i) {     return i; } public string pingpong(string s) {     return s; } public boolean pingpong(boolean b) {     return b; } 

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