javascript - Is there a less "hacky" way to check an items visibility? -


i testing single page app, navigation page revealed when user clicks appropriate icon. wanted check , see prior clicking if page open. on page company name label. visible naked eye when navigation page displayed.

the problem running .isdisplayed() returning true when use that. have used ec.visibilityof() returns true well. below works, not happy , wondering if there better way.

    navigationopenclick() {     if (this.ec.elementtobeselected(this.navpage.companyname)) {         this.navicon.click();     } } 

my brain had flatulence , forgot .isdisplayed() returns promise. once resolved promise, .isdisplayed() worked should.

my not "hacky" working code below:

   navigationopenclick() {     this.navpage.companyname.isdisplayed().then((displayed) => {         if (!displayed) {             this.navicon.click();         };     }); } 

Comments

Popular posts from this blog

aws api gateway - SerializationException in posting new Records via Dynamodb Proxy Service in API -

asp.net - Problems sending emails from forum -