java - How do method references in RxJava work? -


can explain me, how come both of lambdas can replaced method references here?

in rxjava, map() takes parameter of type func1<t, r>, comment states "represents function one argument". understand why valueof(object) works here. trim() takes no arguments @ all.

so how work exactly?

observable.just("")     .map(s -> string.valueof(s))  //lambdas     .map(s -> s.trim())           //      .map(string::valueof)         //method references     .map(string::trim)            //     .subscribe();

i didn't play rx in java, please note, string::valueof static (aka unbound) function, while string::trim non-static (aka bound) function have indirect this argument. so, in fact, both function takes single argument. in java it's not visible in python example.


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