javascript - Ajax form $_POST blank return data - 


var name = jquery('[data-field="name"]').val(); var email = jquery('[data-field="email"]').val(); var inumber = jquery('[data-field="inumber"]').val(); var rnumber = jquery('[data-field="rnumber"]').val(); var date = jquery('[data-field="date"]').val(); var amount = jquery('[data-field="amount"]').val(); var feedback = jquery('[data-field="name"]').val();  var file_attach = new formdata(jquery('input[name^="media"]'));      jquery.each(jquery('input[name^="media"]')[0].files, function(i, file) {     file_attach.append(i, file); }); jquery.ajax({     type: 'post',     data: { func: "sendmail", name,email,inumber,rnumber,date,amount,feedback,file_attach},     url: 'billing-information-mailer.php',     cache: false,     contenttype: false,     processdata: false,     success: function(data){         console.log(data);     } });

i'm trying pass form info , attachment php file send email, went $.post need set processdata false shifted $.ajax, php file sending empty return. code in php file print_r($_post);

edit:

<input type="file" name="media" data-field="billing" id="vdnupload" name="vdnupload" placeholder="proof of payment">

the syntax of object you're providing data property incorrect each item needs key.

however more pressing problem upload file need put data (file , input values) in formdata object , send alone. try this:

var formdata = new formdata();      $.each($('input[name^="media"]')[0].files, function(i, file) {     formdata.append(i, file); }); formdata.append('name', $('[data-field="name"]').val()); formdata.append('email', $('[data-field="email"]').val()); formdata.append('inumber', $('[data-field="rnumber"]').val()); formdata.append('rnumber', $('[data-field="rnumber"]').val()); formdata.append('date', $('[data-field="date"]').val()); formdata.append('amount', $('[data-field="amount"]').val()); formdata.append('feedback', $('[data-field="name"]').val());  $.ajax({     type: 'post',     data: formdata,     url: 'billing-information-mailer.php',     cache: false,     contenttype: false,     processdata: false,     success: function(data){         console.log(data);     } });

you make much, simpler if place form element around inputs want include in request. way can provide reference of form formdata constructor , values populated you:

var formdata = new formdata($('#myform')[0]);

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