python - xarray.where() with multiple conditions -


i have dataarray landcover types. mask out values have in list. possible use xr.where() function multiple conditions?

import numpy np import xarray xr = xr.dataarray(np.arange(25).reshape(5, 5), dims=('x', 'y')) print lc = [10,12,19] a.where((a == lc[0]) | (a == lc[1]))

which gives:

 <xarray.dataarray (x: 5, y: 5)> array([[ 0,  1,  2,  3,  4],        [ 5,  6,  7,  8,  9],        [10, 11, 12, 13, 14],        [15, 16, 17, 18, 19],        [20, 21, 22, 23, 24]]) coordinates:   * x        (x) int64 0 1 2 3 4   * y        (y) int64 0 1 2 3 4  <xarray.dataarray (x: 5, y: 5)> array([[ nan,  nan,  nan,  nan,  nan],        [ nan,  nan,  nan,  nan,  nan],        [ 10.,  nan,  12.,  nan,  nan],        [ nan,  nan,  nan,  nan,  nan],        [ nan,  nan,  nan,  nan,  nan]]) coordinates:   * x        (x) int64 0 1 2 3 4   * y        (y) int64 0 1 2 3 4

the above works 2 landcover values, tedious 30 types. there better way?

xr.dataarray(np.in1d(a, lc).reshape(a.shape),              dims=a.dims, coords=a.coords)

should it:

<xarray.dataarray (x: 5, y: 5)> array([[false, false, false, false, false],        [false, false, false, false, false],        [ true, false,  true, false, false],        [false, false, false, false,  true],        [false, false, false, false, false]], dtype=bool) coordinates:   * x        (x) int64 0 1 2 3 4   * y        (y) int64 0 1 2 3 4

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