sql - TSQL - How to return rows with a specific value last? -


my question reverse of question.

tsql - possible define sort order?

i want return records sql server database, sorted in ascending order based on column's value 2 particular records should on end.

the original sql (which needs changed) below:

select code_id categoryid, code_desc categorydescription codes code_id > '000001' , code_id < '000100' order categorydescription

the results returned

  • 000003 ***first record
  • 000002 ***another record
  • 000004 apple
  • 000016 books
  • 000014 cables

i want below result (first 2 asteriks on last):

  • 000004 apple
  • 000016 books
  • 000014 cables
  • 000003 ***first record
  • 000002 ***another record

i tried below union statement resultset automatically sorted in ascending order , 2 rows in beginning default.

select code_id categoryid, code_desc categorydescription codes code_id > '000003' , code_id < '000100'  --order categorydescription  union  select code_id categoryid, code_desc categorydescription codes code_id > '000001' , code_id < '000004'

if wish maintain union this:

select * (     select 't' success,  code_id categoryid, code_desc categorydescription, 1 order     codes     code_id > '000003' , code_id < '000100'       union      select 't' success,  code_id categoryid, code_desc categorydescription, 2 order     codes     code_id > '000001' , code_id < '000004' ) x order x.order

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