android - Get random numbers again and again if answer given by user is wrong -

i developing simple dialog box has 2 textviews 1 edittext , 1 submit button. want put random numbers in 2 textviews , multiply them. user has give correct answer finish application. if failed again next random numbers generated , on until user gives right answer.

i have manage work when user gives wrong answer unable generate next 2 random numbers , on. code dialog box is:

final textview t1 = (textview)dialog1.findviewbyid(r.id.textview2); final textview t2= (textview)dialog1.findviewbyid(r.id.textview); final edittext edittext = (edittext) dialog1.findviewbyid(r.id.edit1); textview submit = (textview)dialog1.findviewbyid(r.id.submit);  final int number = (new random().nextint(100)); final int number1 = (new random().nextint(100)); t1.settext(string.valueof(number)); t2.settext(string.valueof(number1));  submit.setonclicklistener(new view.onclicklistener() {      @override     public void onclick(view v) {         string = edittext.gettext().tostring();         if (integer.parseint(a) == number*number1) {          activitya.this.finish();         } else {          }     }  }); 

please me write else part if user gives wrong answer next numbers generated , if after few wrong answers user gives right answer app finishes. needed

int number,number1;// declare before oncreate   number = (new random().nextint(100)); number1 = (new random().nextint(100)); t1.settext(string.valueof(number)); t2.settext(string.valueof(number1));  submit.setonclicklistener(new view.onclicklistener() {  @override public void onclick(view v) {     string = edittext.gettext().tostring();     if (integer.parseint(a) == number*number1) {      activitya.this.finish();     }   else {  //regenerate random numbers.  number = (new random().nextint(100));  number1 = (new random().nextint(100));  t1.settext(string.valueof(number));  t2.settext(string.valueof(number1));  edittext.settext(null);     }    }  });