Choose between either condition using if with logical OR in java -

this might seems bit foolish, has caught me.

i want throw error if charstring doesn't contain word "hi".

so wrote

if(!charstring.contains("hi"))    /// throw error on screen

now, requirement changed. want throw error if charstring not contain "hello".

so, requirement should not throw error if charstring contains either hi or hello

so wrote:

if(!charstring.contains("hi") || !charstring.contains("hello"))    /// throw error on screen

to horror, realized terribly wrong in writing above code. how can write in single if statement then?

the requirement is:

"if charstring contains either hi or hello, not throw error"

a very clear way (at expense of superfluous block requires comment) write

if (charstring.contains("hi") || charstring.contains("hello")){     // nothing } else {     // throw error }

this equivalent less eyebrow-raising

if (!(charstring.contains("hi") || charstring.contains("hello"))){     // throw error }

if (!charstring.contains("hi") && !charstring.contains("hello"))){     // throw error }

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