mysql - PHP validation if not exists price -


i have 2 inputs price1 , price2. , if have 1 price add price1 , price2 empty. want add database , in database in price 2 doesnt have

php:

if(isset($_post["submitmenu"])){ $menu_item_category  = $_post["menu_item_category"]; $menu_item_name      = $_post["menu_item_name"]; $menu_item_details   = $_post["menu_item_details"]; $menu_price1         = $_post["menu_price1"]; $menu_price2         = $_post["menu_price2"];  $query_orders = "insert menus (menu_item_category,menu_item_name,menu_item_details, menu_price1, menu_price2)  values ('$menu_item_category','$menu_item_name','$menu_item_details', '$menu_price1', '$menu_price2');"; mysqli_query($con, $query_orders); }

sql:

create table if not exists `menus` (   `menu_item_id` int(10) not null auto_increment,   `menu_item_category` varchar(100) not null,   `menu_item_name` varchar(100) not null,   `menu_item_details` varchar(300) default null,   `menu_price1` double not null,   `menu_price2` double not null,   `menu_date` timestamp null default null,   primary key (`menu_item_id`) ) engine=innodb  default charset=latin1 auto_increment=244 ;

its working when add 2 prices.

example:

price1 = 20

price2 = 30

then working , sending database. if dont insert price price2 not sending database.

example:

price1 = 20

price2

the issue table set menu_price2 not null. either alter table allow null or try 

$menu_price2 = empty($_post["menu_price2"]) ? $_post["menu_price2"] : 0;

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