c++ - Checking if a char is pressed -


the program should read 2 ints , calculate sum or product depending on symbol introduced keyboard. if press q @ given momement, must exit.

#include "stdafx.h" #include <iostream> #include<conio.h>  using namespace std;  int main() {  char k, l ='h',c;      int a,b,s, p;               aici: while (l != 'q') {      cin >> a;       if (_kbhit() == 0) //getting out of loop     {         c = a;         if (c == 'q')         {             l = 'q';             goto aici;         }     }       cin >> b;      if (_kbhit() == 0)     {         c = b;         if (c == 'q')         {             l = 'q';             goto aici;         }     }       k = _getch();      if (_kbhit() == 0)     {         c = k;         if (c == 'q')         {             l = 'q';             goto aici;         }     }       if (k == '+')     {          s =(int)(a + b);         cout << s;     }     if (k == '*')     {         p = (int)(a*b);         cout << p;     } } return 0; }

it expects both , b ints typing 'q' makes total mess. possible make program work without having , b declared chars?

you don't need use goto , kbhit() inside cin. simpel way is:

#include <iostream> #include <string>  using namespace std;  int main() {     int a,b;     string a, b     char k;      while(1)     {         cin >> a;         if(a == "q") break;         cin >> b;         if(b == "q") break;          = atoi(a.c_str());         b = atoi(b.c_str());          cin >> k;         if(k == 'q') break;          if (k == '+')             cout << (a + b);         if (k == '*')             cout << (a*b);      } }

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