javascript - a non-empty list of integers -


this question has answer here:

you given non-empty list of integers. task, should return list consisting of non-unique elements in list. need remove unique elements (elements contained in given list once). when solving task, not change order of list. example: [1, 2, 3, 1, 3] 1 , 3 non-unique elements , result [1, 3, 1, 3].

function nonuniqueelements(data) {   var array = [];   (var = 0; < data.length; i++) {       while (i >= 2) {          array.push(i);       }       return data;   } }

my solution:

  1. first loop on array count how each number appears in array
    using map. total time o(n)

  2. and loop again on array , push new array number, if current number appears more 1 in map. total time o(n).

     function nonuniqueelements(data) {            //first loop on array , find duplications           //create map numbers           //the key number,            //and value how each number appears in array           var map = {};           (var i=0; < data.length; i++){             if (map[data[i]] == undefined){               //the number not exist in map, push map                map[data[i]] = 0;              } else {//the number alredy exists               //increase counter                map[data[i]] = map[data[i]] +1;             }           }             //now, loop on array once again           var nonuniquearray = [];             (var i=0; < data.length; i++){               //if value of current element more 1               if (map[data[i]] > 0){                 //push new nonuniquearray                 nonuniquearray.push(data[i]);               }             }            //return  non unique array           return nonuniquearray;         }

hope helps


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